In linear algebra, a nilpotent matrix is a square matrix N such that
N^k = 0\,
for some positive integer k. The smallest such k is called the index of N,[1] sometimes the degree of N.
More generally, a nilpotent transformation is a linear transformation L of a vector space such that L^k = 0 for some positive integer k (and thus, L^j = 0 for all j \geq k).[2][3][4] Both of these concepts are special cases of a more general concept of nilpotence that applies to elements of rings.
Examples
Example 1
The matrix
A = \begin{bmatrix} 0 & 1 \\ 0 & 0 \end{bmatrix}
is nilpotent with index 2, since A^2 = 0.
Example 2
More generally, any n-dimensional triangular matrix with zeros along the main diagonal is nilpotent, with index \le n [citation needed]. For example, the matrix
B=\begin{bmatrix} 0 & 2 & 1 & 6\\ 0 & 0 & 1 & 2\\ 0 & 0 & 0 & 3\\ 0 & 0 & 0 & 0 \end{bmatrix}
is nilpotent, with
B^2=\begin{bmatrix} 0 & 0 & 2 & 7\\ 0 & 0 & 0 & 3\\ 0 & 0 & 0 & 0\\ 0 & 0 & 0 & 0 \end{bmatrix} ;\ B^3=\begin{bmatrix} 0 & 0 & 0 & 6\\ 0 & 0 & 0 & 0\\ 0 & 0 & 0 & 0\\ 0 & 0 & 0 & 0 \end{bmatrix} ;\ B^4=\begin{bmatrix} 0 & 0 & 0 & 0\\ 0 & 0 & 0 & 0\\ 0 & 0 & 0 & 0\\ 0 & 0 & 0 & 0 \end{bmatrix}
The index of B is therefore 4.
Example 3
Although the examples above have a large number of zero entries, a typical nilpotent matrix does not. For example,
C=\begin{bmatrix} 5 & -3 & 2 \\ 15 & -9 & 6 \\ 10 & -6 & 4 \end{bmatrix} \qquad C^2=\begin{bmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{bmatrix}
although the matrix has no zero entries.
Example 4
Additionally, any matrices of the form
\begin{bmatrix} a_1 & a_1 & \cdots & a_1 \\ a_2 & a_2 & \cdots & a_2 \\ \vdots & \vdots & \ddots & \vdots \\ -a_1-a_2-\ldots-a_{n-1} & -a_1-a_2-\ldots-a_{n-1} & \ldots & -a_1-a_2-\ldots-a_{n-1} \end{bmatrix}
such as
\begin{bmatrix} 5 & 5 & 5 \\ 6 & 6 & 6 \\ -11 & -11 & -11 \end{bmatrix}
or
\begin{bmatrix} 1 & 1 & 1 & 1 \\ 2 & 2 & 2 & 2 \\ 4 & 4 & 4 & 4 \\ -7 & -7 & -7 & -7 \end{bmatrix}
square to zero.
Example 5
Perhaps some of the most striking examples of nilpotent matrices are n\times n square matrices of the form:
\begin{bmatrix} 2 & 2 & 2 & \cdots & 1-n \\ n+2 & 1 & 1 & \cdots & -n \\ 1 & n+2 & 1 & \cdots & -n \\ 1 & 1 & n+2 & \cdots & -n \\ \vdots & \vdots & \vdots & \ddots & \vdots \end{bmatrix}
The first few of which are:
\begin{bmatrix} 2 & -1 \\ 4 & -2 \end{bmatrix} \qquad \begin{bmatrix} 2 & 2 & -2 \\ 5 & 1 & -3 \\ 1 & 5 & -3 \end{bmatrix} \qquad \begin{bmatrix} 2 & 2 & 2 & -3 \\ 6 & 1 & 1 & -4 \\ 1 & 6 & 1 & -4 \\ 1 & 1 & 6 & -4 \end{bmatrix} \qquad \begin{bmatrix} 2 & 2 & 2 & 2 & -4 \\ 7 & 1 & 1 & 1 & -5 \\ 1 & 7 & 1 & 1 & -5 \\ 1 & 1 & 7 & 1 & -5 \\ 1 & 1 & 1 & 7 & -5 \end{bmatrix} \qquad \ldots
These matrices are nilpotent but there are no zero entries in any powers of them less than the index.[5]
Example 6
Consider the linear space of polynomials of a bounded degree. The derivative operator is a linear map. We know that applying the derivative to a polynomial decreases its degree by one, so when applying it iteratively, we will eventually obtain zero. Therefore, on such a space, the derivative is representable by a nilpotent matrix.
Characterization
For an n \times n square matrix N with real (or complex) entries, the following are equivalent:
Nis nilpotent.- The characteristic polynomial for
Nis\det \left(xI - N\right) = x^n. - The minimal polynomial for
Nisx^kfor some positive integerk \leq n. - The only complex eigenvalue for
Nis 0.
The last theorem holds true for matrices over any field of characteristic 0 or sufficiently large characteristic. (cf. Newton's identities)
This theorem has several consequences, including:
- The index of an
n \times nnilpotent matrix is always less than or equal ton. For example, every2 \times 2nilpotent matrix squares to zero. - The determinant and trace of a nilpotent matrix are always zero. Consequently, a nilpotent matrix cannot be invertible.
- The only nilpotent diagonalizable matrix is the zero matrix.
See also: Jordan–Chevalley decomposition#Nilpotency criterion.
Classification
Consider the n \times n (upper) shift matrix:
S = \begin{bmatrix} 0 & 1 & 0 & \ldots & 0 \\ 0 & 0 & 1 & \ldots & 0 \\ \vdots & \vdots & \vdots & \ddots & \vdots \\ 0 & 0 & 0 & \ldots & 1 \\ 0 & 0 & 0 & \ldots & 0 \end{bmatrix}.
This matrix has 1s along the superdiagonal and 0s everywhere else. As a linear transformation, the shift matrix "shifts" the components of a vector one position to the left, with a zero appearing in the last position:
S(x_1,x_2,\ldots,x_n) = (x_2,\ldots,x_n,0).[6]
This matrix is nilpotent with degree n, and is the canonical nilpotent matrix.
Specifically, if N is any nilpotent matrix, then N is similar to a block diagonal matrix of the form
\begin{bmatrix} S_1 & 0 & \ldots & 0 \\ 0 & S_2 & \ldots & 0 \\ \vdots & \vdots & \ddots & \vdots \\ 0 & 0 & \ldots & S_r \end{bmatrix}
where each of the blocks S_1,S_2,\ldots,S_r is a shift matrix (possibly of different sizes). This form is a special case of the Jordan canonical form for matrices.[7]
For example, any nonzero 2 × 2 nilpotent matrix is similar to the matrix
\begin{bmatrix} 0 & 1 \\ 0 & 0 \end{bmatrix}.
That is, if N is any nonzero 2 × 2 nilpotent matrix, then there exists a basis b1, b2 such that Nb1 = 0 and Nb2 = b1.
This classification theorem holds for matrices over any field. (It is not necessary for the field to be algebraically closed.)
Flag of subspaces
A nilpotent transformation L on \mathbb{R}^n naturally determines a flag of subspaces
\{0\} \subset \ker L \subset \ker L^2 \subset \ldots \subset \ker L^{q-1} \subset \ker L^q = \mathbb{R}^n
and a signature
0 = n_0 < n_1 < n_2 < \ldots < n_{q-1} < n_q = n,\qquad n_i = \dim \ker L^i.
The signature characterizes L up to an invertible linear transformation. Furthermore, it satisfies the inequalities
n_{j+1} - n_j \leq n_j - n_{j-1}, \qquad \mbox{for all } j = 1,\ldots,q-1.
Conversely, any sequence of natural numbers satisfying these inequalities is the signature of a nilpotent transformation.
Generalizations
A linear operator T is locally nilpotent if for every vector v, there exists a k\in\mathbb{N} such that
T^k(v) = 0.\!\,
For operators on a finite-dimensional vector space, local nilpotence is equivalent to nilpotence.
Notes
- ^ Herstein (1975, p. 294)
- ^ Beauregard & Fraleigh (1973, p. 312)
- ^ Herstein (1975, p. 268)
- ^ Nering (1970, p. 274)
- ^ Mercer, Idris D. (31 October 2005). "Finding "nonobvious" nilpotent matrices". idmercer.com. self-published; personal credentials: PhD Mathematics, Simon Fraser University. Retrieved 5 April 2023.
- ^ Beauregard & Fraleigh (1973, p. 312)
- ^ Beauregard & Fraleigh (1973, pp. 312,313)
References
- Beauregard, Raymond A. & Fraleigh, John B. (1973), A First Course In Linear Algebra: with Optional Introduction to Groups, Rings, and Fields, Boston: Houghton Mifflin Co., ISBN 0-395-14017-X
- Herstein, I. N. (1975), "Topics In Algebra", 2nd ed., John Wiley & Sons
- Nering, Evar D. (1970), "Linear Algebra and Matrix Theory", 2nd ed., New York: Wiley, LCCN 76091646